JS - 获取 url 参数
function getUrlParam(name) {
var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)");
var r = decodeURI(window.location.search.substr(1)).match(reg);
if (r != null) {
return unescape(r[2]);
}else{
return null;
}
}